Saturday, August 14, 2010

Free algebra help

I am here today to solve some free algebra 2 homework help for my friends how asked for help. I will solve some simple problem which will help you understand the concept perfectly.

Lets solve algebra 2 answers below.

Solve the given math algebra 1 problem for step by step use the elimination method.

14x + 44y = 116

18x + 22y = 80

Solution:

Within a problem, we have to eliminate any one variable,

First we are going to increase (multiply) the equation 2 with 2

14x + 44y = 116

36x + 44y = 160 (subtracting)

- 22x = -44

x =2

Next we are going to alternate (Substitute) the value of x on equation 1.

14(2) + 44y = 116

28+44y=116

44y=88

Y=2

The final answer is x = 2,y = 2.

Once you work on some more similar problem get that checked by algebra 2 answers online, if you are wrong you can correct yourself. Bye....

Thursday, August 12, 2010

Calculus Help

Guys this is just an advice to those friends, who are looking for Free calculus help First learn the introduction of calculus before we proceed.

Introduction of calculus:- The topics involved in calculus are functions, limits, derivatives, application of derivatives, logarithm functions, trig functions and exponential functions. The two major sub divisions of calculus are differential calculus and integral calculus. In this article we shall discuss about the introduction to calculus. The following are the examples involved in Introduction to calculus.

If you need to practice just look at sites which will help you with free calculus problems and i wanted to know is are you aware that we have free calculus tutoring these days.

Monday, August 9, 2010

1 pound in dollars


I have a simple example which will help you understand how to convert 1 pound in dollars. This will help you when you go out to shop. So understand the concept well.

We been understanding other concepts of mathematics by working simple problems of mathematics lets look at the example below.

Example:-

If you are on a visit to United States of America, but you belong to England. You have with you 350 pounds. You go to the nearby shopping mall and buy a wine. The rate of wine is 200 dollars, what is the amount left with you now.

Solution:

Formula for converting pounds to dollar

1 pound 1.51 dollars

Multiplied by 350 for both sides

350 pounds 528.5 dollars

Now you give 350 pounds to shopper.

528.5 - 200 dollars = 328.5 dollars converted into pounds.

Answer: The amount left with you is 328.5 $

Look at the example, there are a few things that you observe in this example carefully such as look at how to convert1 pound in dollars along with the formula to do so. The other things i would like you to see is the dollar sign or $ this is the symbol used for dollar. We have many more math signs you will come across every day

Monday, August 2, 2010

Greater than sign

Good morning my little friends, look at the frogs here------> What do they say?

These frogs show you the greater than sign and lesser than sign here. Do you know what are these signs? We have learn t a lot about different numbers previously now lets learn these great than or lesser than signs in detail.

These signs gives us the difference in the numbers which is an essential concept in mathematics. In mathematics the symbol for "what or which is greater than"is ">"

The example below will help you understand this concept better.


George has 10 chocolates and Jane has 7
chocolates. Write this statement by using greater than sign.

Solution:


George: Number of chocolates = 10

Jane : Number of chocolates =7


7 is a lower value. Hence the statement is written as 10 >7.
This concept is useful to the higher grades as it is useful to my 5th grade math friends.

Check it out and let me know your comments on this and look how George is enjoying the chocolate below.


o

Thursday, July 22, 2010

Trigonometry problems

Hi friends...Good morning....I am here with you guys to discuss on trigonometry problems as i promised you earlier. Some problems on trigonometry have already been discussed look into them too.

Look for an example of trigonometry problem below.

If the distance of John standing from a wall is 100 m and the angle subtended by the top of the wall with the ground is 30o, measure the height of the wall in meters?

Solution:

* AB = distance of the man from the wall = 100 m

* BC = height of the wall = h (which has to be calculated)

* The trigonometric function that uses AB and BC is tan A , where A = 30o.

So tan 30o = BC / AB = h / 100

Therefore height of the wall h = 100 tan 30o = (100) 1/√3 = 57.74 m.

Lets work on coterminal angles in our next post....Guys practice many more such problems...

Tuesday, July 13, 2010

Trigonometry functions

Ari thematic, algebra, geometry, trigonometry are subjects which children like it world wide, i use to like mathematics a lot when i was in school. I enjoyed it and therefore wanted to share my knowledge with you guys. I had posted one post earlier also which has introduction on trigonometry.

Today when i was thinking what to start up, trigonometry functions struck to my mind. I decided to write on it, so here i am with it.

Trigonometry functions are also called as circular functions. They are functions of the angles. They are normally used to relate the angles of the triangle to the sides of the triangle. All trignometry terms are related to trigonometric functions. The basic trigonometric functions are Sine, Cosine and tangent, cot sec, cosec functions of a triangle. With all this it make us easy to find the sides of the triangle. Now let me give you the introduction of trigonometric identities.


Brief introduction of trigonometric identities:- Trigonometric identities are basically formed as the equalities is involve trigonometric functions and they prove to be true for every single value of the occurring. An identity is a basic equation that represents true for all of the possible values of its variables. Trigonometric identities are important; they involve the sums or differences of trigonometric angles.

We will solve these problems in my next post. Wait until then. But you will have to post your comment on this first.

Friday, July 9, 2010

Some problems on Trigonometry

Do you know a fact guys, how was the measurement of heights and distance of an object were calculated in the ancient times? No idea right..i am sure you are not aware of it, even for me it was a new thing to know. Trigonometry, yes friends it was calculated with the help of trigonometry.

Look for some trigonometry worksheets and work on them, to increase your knowledge. I have a few solved problem that will help you. Introduction to trigonometry is already given to you in my previous post, check that as well. Look below for some solved trigonometry problems.

Problem No1.

Let’s assume that the distance of a person from a tower is 100 m and the angle subtended by the top of the tower with the ground is 30o, now let’s calculate what the height of the tower in meters is? Below are the steps to solve the problem.

Steps:

  1. Draw a simple diagram to represent the problem. Label it carefully and clearly mark out the quantities that are given and those which have to be calculated. Denote the unknown dimension by say h if you are calculating height or by x if you are calculating distance.
  2. Identify which trigonometric function represents a ratio of the side about which information is given and the side whose dimensions we have to find out. Set up a trigonometric equation.
  3. Substitute the value of the trigonometric function and solve the equation for the unknown variable.

Solution:

  1. AB = distance of the man from the tower = 100 m
  2. BC = height of the tower = h (to be calculated)
  3. The trigonometric function that uses AB and BC is tan A, where A = 30o.
  4. So tan 30o = BC/AB=h/100

Therefore we conclude height of the tower h= 100 tan 30o = (100)/√3 =57.74m.



Problem No 2:-

Prove the given trig expression 1 + cot A/ 1 + tan A = 1 + cos A/ sin A + tan A

Solution:

Given

1 + cot A/ 1 + tan A = 1 + cos A/ sin A + tan A

Let us take L.H.S and we prove the R.H.S

L.H.S = 1 + cot A/ 1 + tan A

Here cot A = 1/ tan A

= 1 + (1/ tan A) / 1 + tan A

= (tan A + 1/ tan A) / 1 + tan A

= 1 + tan A/ (1 + tan A) tan A

L.H.S = cot A

R.H.S = 1 + cos A/ sin A + tan A

= 1 + cos A/ (sin A + (sin A/ cos A))

= 1 + cos A/ (sin A cos A + sin A/ cos A)

= 1 + cos A/ sin A(cos A + 1)/cos A

= (1 + cos A) cos A/ (cos A + 1) sin A

= cos A / sin A

R.H.S = cot A

Hence L.H.S = R.H.S


These problems will give you a clear idea on how to solve problems on trigonometry, but that is of no use until you don't work on it so what are you waiting for, start working on it immediately. Let me know how informative you found this post.