Look for an example of trigonometry problem below.
If the distance of John standing from a wall is 100 m and the angle subtended by the top of the wall with the ground is 30o, measure the height of the wall in meters?
Solution:
* AB = distance of the man from the wall = 100 m
* BC = height of the wall = h (which has to be calculated)
* The trigonometric function that uses AB and BC is tan A , where A = 30o.
So tan 30o = BC / AB = h / 100
Therefore height of the wall h = 100 tan 30o = (100) 1/√3 = 57.74 m.
Lets work on coterminal angles in our next post....Guys practice many more such problems...
Ari thematic, algebra, geometry, trigonometry are subjects which children like it world wide, i use to like mathematics a lot when i was in school. I enjoyed it and therefore wanted to share my knowledge with you guys. I had posted one post earlier also which has introduction on trigonometry.
Today when i was thinking what to start up, trigonometry functions struck to my mind. I decided to write on it, so here i am with it.
Trigonometry functions are also called as circular functions. They are functions of the angles. They are normally used to relate the angles of the triangle to the sides of the triangle. All trignometry terms are related to trigonometric functions. The basic trigonometric functions are Sine, Cosine and tangent, cot sec, cosec functions of a triangle. With all this it make us easy to find the sides of the triangle. Now let me give you the introduction of trigonometric identities.
Brief introduction of trigonometric identities:- Trigonometric identities are basically formed as the equalities is involve trigonometric functions and they prove to be true for every single value of the occurring. An identity is a basic equation that represents true for all of the possible values of its variables. Trigonometric identities are important; they involve the sums or differences of trigonometric angles.
We will solve these problems in my next post. Wait until then. But you will have to post your comment on this first.
Do you know a fact guys, how was the measurement of heights and distance of an object were calculated in the ancient times? No idea right..i am sure you are not aware of it, even for me it was a new thing to know. Trigonometry, yes friends it was calculated with the help of trigonometry.
Look for some trigonometry worksheets and work on them, to increase your knowledge. I have a few solved problem that will help you. Introduction to trigonometry is already given to you in my previous post, check that as well. Look below for some solved trigonometry problems.
Problem No1.
Let’s assume that the distance of a person from a tower is 100 m and the angle subtended by the top of the tower with the ground is 30o, now let’s calculate what the height of the tower in meters is? Below are the steps to solve the problem.
Steps:
Draw a simple diagram to represent the problem. Label it carefully and clearly mark out the quantities that are given and those which have to be calculated. Denote the unknown dimension by say h if you are calculating height or by x if you are calculating distance.
Identify which trigonometric function represents a ratio of the side about which information is given and the side whose dimensions we have to find out. Set up a trigonometric equation.
Substitute the value of the trigonometric function and solve the equation for the unknown variable.
Solution:
AB = distance of the man from the tower = 100 m
BC = height of the tower = h (to be calculated)
The trigonometric function that uses AB and BC is tan A, where A = 30o.
So tan 30o = BC/AB=h/100
Therefore we conclude height of the tower h= 100 tan 30o = (100)/√3 =57.74m.
Problem No 2:-
Prove the given trig expression 1 + cot A/ 1 + tan A = 1 + cos A/ sin A + tan A
Solution:
Given
1 + cot A/ 1 + tan A = 1 + cos A/ sin A + tan A
Let us take L.H.S and we prove the R.H.S
L.H.S = 1 + cot A/ 1 + tan A
Here cot A = 1/ tan A
= 1 + (1/ tan A) / 1 + tan A
= (tan A + 1/ tan A) / 1 + tan A
= 1 + tan A/ (1 + tan A) tan A
L.H.S = cot A
R.H.S = 1 + cos A/ sin A + tan A
= 1 + cos A/ (sin A + (sin A/ cos A))
= 1 + cos A/ (sin A cos A + sin A/ cos A)
= 1 + cos A/ sin A(cos A + 1)/cos A
= (1 + cos A) cos A/ (cos A + 1) sin A
= cos A / sin A
R.H.S = cot A
Hence L.H.S = R.H.S
These problems will give you a clear idea on how to solve problems on trigonometry, but that is of no use until you don't work on it so what are you waiting for, start working on it immediately. Let me know how informative you found this post.
Hi friends...Good morning....I am here with you guys to discuss on trigonometry problems as i promised you earlier. Some problems on trigonometry have already been discussed look into them too.